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FLOTATION CALCULATION METHODS
Flotation standards for recreational boats. How to calculate flotation amounts.
One of the more important tasks a builder must perform for a small boat is determining weight and persons capacity, calculating how much flotation is needed and making a label for the boat. Also attaching a Hull Identification Number (HIN) is required.
For back yard boat builders in the US, who are building a boat for themselves, an HIN can be obtained from the state office that registers boats. When registering the boat tell them it is a home built boat. They will have you fill out a form declaring that you built the boat, and assign an HIN.
In Canada this number is available from the Canadian Office of Boating Safety: Canadian Office of Boating Safety Regulations http://www.tc.gc.ca/eng/marinesafety/debs-obs-construction-menu-2029.htm
Methods of Calculating Capacity:
Many people consider calculating capacities and flotation as some mysterious scientific process beyond the capabilities of the average boat builder. This is definitely not true. Anyone with a basic education can do it. If you can add and subtract, multiply and divide, you can calculate boat capacities and flotation. For a boat like the FL 12 it is even simpler because the shapes are all squares, rectangles and triangles. You need to be able to find area and volume.
Area of any rectangle is the length times width.
Area of a square is one side times itself (or length times width but in this case the length equals the width)
The area of a triangle equals the base of the triangle (the bottom width) times the height, divided by two.
Volume involves one more dimension, the thickness or depth. So the volume of a box is the length of the box times the width times the depth.
The same applies to a triangular shapes.
Any boat like the FL12 that has a flat bottom, or even a vee bottom can be divided up into these shapes and the volume of each shape is found. Then the volumes are added up. The total volume times the weight of water (62.4 pounds per cubic foot) equals the displacement.
As shown in the below illustration the volume of this shape is relatively simple to calculate by simplifying the shape and taking each piece at a time.
Length W1 + W2 divided by 2 is the average width, W, of the front side of the box.
(W1 + W2)/2 times height b gives the area of the front of the box,
Find the area of the back face using the same method.
Then add the two areas together and divide by two to get the average area. Multiply the average area by the width of the box (length e) to get the volume of the box.
By doing this for each section of the boat, and then adding up the volumes, you get the total volume of the boat.
Displacement is the weight of the water that is moved out of the way when you make a hole in the water by putting a boat in it. Displacement divided by five is the maximum weight capacity. If you subtract the weight of the outboard motor, battery, and a portable fuel tank, you get maximum persons capacity. That weight plus 32 and divided by 141 equals the number of person.
Of course the simplest way to do this is put weight in the boat. Add weights until water is about to come in. The total weight is the displacement weight. Divide the total by five, and that gives you maximum weight capacity. Subtract the weight of the outboard motor, battery, and a portable fuel tank and you have persons weight. Add 32 to persons weight and divide by 141 to get persons.
An easy way to find persons capacity is to put weight on one side of the boat as far outboard as possible. Add weight until the boat heels to the point where water comes in. Divide that weight by 0.6 (or multiply by 1.6667) and that is the maximum persons Weight.
Add the engine weight, battery, and a portable fuel tank, to the Maximum Persons Weight and multiply by five and you have the Maximum Weight Capacity.
For the FL 12 I divided the boat into 10 equal sections. Each section forms a box. Then I measured the dimensions of each box to get the volume.
Starting at the bow. The bow section, shown here as Box A, forms a triangular shaped box. Box A is 10" by 18" by 21"
10" = 0.8333 ft
18 1/2" = 1.54 ft
21 1/2" = 1.79 ft
The formula is 0.8333 X 1.54 / 2 = 0.642
Then multiply 1.79 X 0.642 / 2 = 0.5746= volume of Box 1
Box B is a little more complicated because one side is large than the other side. That is the rear side is bigger than the front side.
The front side is 21 1/2 by 18 1/4 by 11 1/2.It is not a rectangle, but since two sides are the same length we can treat it the same as a rectangle by using the average of the length of the two unequal sides.
21 + 11 1/2 = 32 1/2 32 1/2 / 2 = 16 1/4 = 1.354 front area
the rear side = 28 3/4 by 22 by 18 1/2
28 3/4 + 22 = 50 3/4 50 3/4 / 2 = 25 3/8 = 2.115 rear area
2.115 + 1.354 = 3.469 3.469 / 2 = 1.7345 Avg. area
1.7345x 18 1/4 = 1.756 X 1.54 = 2.671 volume of box 2
By dividing the boat into many boxes, ten is good number, but you can use more for bigger boats, calculating the volume of each box, and added up the volumes you get the volume of the boat. Then if you multiply the volume by 62.4 you find the displacement weight.
For the FL12 I divided the boat into ten sections and calculated the volume of the blocks between each section.
Then divide the displacement weight by five to get the maximum weight capacity. Subtract the weight of the outboard motor for persons weight. Get the weight of the motor from USCG Table 4 or ABYC S-10. To get the number of people add 32 to the persons weight and divide by 141.
But I wanted to see how this compares to doing it by using Simpson's Formula to see how accurate it is.
By using both methods the results were very close to each other, and the number of persons was the same.
This method is not limited to flat bottom boats. Boats with more complex shapes can use the same method. The following illustrates a vee bottom boat.
Each block can be split into triangles, rectangles and squares. The areas and volumes are simple to calculate. Curves to the shape can be considered as straight lines if you break it into smaller blocks.
Once you know the capacities calculating flotation is next.
You need to find the amount of flotation to float three things;
The Boat: The boat is plywood. The boat weighs 100 lbs. Plywood is buoyant so the amount need is negative, that is the plywood provides some flotation. Flotation foam at 2 lb. per cubic foot supports 60.4 lbs.
Boat Weight (Wh) X a factor for plywood (-0.81) divided by 60.4 = Cubic feet = -1.34
The outboard motor: a 2HP motor weighs 25 lbs according to Table 4 and S-10. For 2 HP motor there is no battery or fuel tank weight.
Engine Weight (25) divided by 60.4 = 0.413907
The people. People don't weigh as much in water as they do in air. Plus that it is assumed that with flotation, part of the persons body will be out of the water so the factor is 2/15. But in the USCG Guidelines they use 1/4, or 0.25. This gives you a safety factor of about two for the amount of flotation for persons weight.
Persons weight (627.72 x 0.25) divided by 60.4 equals 2.639611
Total Flotation = 0.413907 + 2.639611 - 1.34106 = 1.712458
Round this to 1.75 or even two.
Place the flotation for the engine in the back. Split it in two and put half in the starboard quarter and the other in the port quarter. This supports and balances the engine weight. Divide the persons flotation up and put it under the seats so that it will stabilize the boat when it is swamped.
Revised 04/11/2012 http://newboatbuilders.com/ Copyright 2009 All Rights Reserved.